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What is the rectangular coordinate form of the polar coordinates #(r, pi/6)# ?

1 Answer

May 3, 2016

#(r, pi/6)# in polar form is #(sqrt(3)/2 r, r/2)# in rectangular form

Explanation:

#theta = pi/6# only gives you the angle.

You need a radius too, but #(r, pi/6)# in polar form is #(sqrt(3)/2r, r/2)# in rectangular form.

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#pi/6# is one half of an internal angle of an equilateral triangle.

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