Question #c814d

1 Answer
Stefan V.
Apr 6, 2016

"3.5% m/v"3.5% m/v

Explanation:

I'm assuming that the problem wants you to find the mass by volume percent concentration, "% m/v"% m/v, for this calcium chloride solution.

A solution's mass by volume percent concentration tells you how many grams of solute, which in your case is calcium chloride, "CaCl"_2CaCl2, are present in "100 mL"100 mL of solution.

This means that in order to find a solution's "% m/v"% m/v concentration, you essentially have to determine how many grams of solute you get in "100 mL"100 mL of said solution.

In your case, you know that "250 mL"250 mL of this solution contain "8.56 g"8.56 g of calcium chloride, which means that "100 mL""100 mL will contain

100 color(red)(cancel(color(black)("mL"))) * "8.56 g CaCl"_2/(250color(red)(cancel(color(black)("mL")))) = "3.46 g CaCl"_2

So, if this is how much solute you get per "100 mL" of solute, you can say that the solution's "%m/v" concentration is equal to

"% m/v" = color(green)(|bar(ul(color(white)(a/a)"3.5% CaCl"_2color(white)(a/a)|))) -> rounded to two sig figs

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