Question #dc792

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Question #dc792

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Answer 1 · 2016-04-23T07:36:04

$1 = r csc (θ)$ $1=rcsc(theta)$
$\Rightarrow 1 = \frac{r}{sin (θ)} = \frac{r^{2}}{r sin (θ)} = \frac{x^{2} + y^{2}}{y}$ $=>1=r/sin(theta)=r^2/(rsin(theta))=(x^2+y^2)/y$
$x^{2} + y^{2} = y$ $x^2+y^2=y$

putting $y = r sin θ and x^{2} + y^{2} = r^{2}$ $y=rsintheta and x^2+y^2=r^2$

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Question #dc792

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