What is the concentration of #1.12*L# of carbon dioxide gas?

1 Answer
anor277
Apr 25, 2016

Approx. #0.9*mol*L^-1#

Explanation:

#CaCO_3(s) + 2HCl(aq) rarr CaCl_2(aq) + H_2O(l) + CO_2(g)uarr#

We assume that the gas was collected at #298*K# and at #1# #atm# pressure. Under these conditions, #1# #mol# of gas, any gas, has a volume of #25.4*L#

So moles of #CO_2# #=# #(1.12*cancelL)/(25.4*cancelL*mol^-1)# #=# #4.41xx10^-2*mol#

Now form the stoichiometric equation, for each mole of gas produced, there were 2 mole of hydrochloric acid.

Thus #"Concentration"# #=# #(2xx4.41xx10^-2*mol)/(0.100*L)# #=# #??*mol*L^-1#

This is a slight over estimate in that the gas collected is saturated with water vapour. This saturated vapour pressure should be subtracted from the pressure.

Related questions
See all questions in Gas Stoichiometry
Impact of this question
1883 views around the world
You can reuse this answer
Creative Commons License