Question #fb855
1 Answer
Mar 15, 2016
Explanation:
- The equation is
#CaCO_3->CaO + CO_2# - Find the formula masses of
#CO_2# and#CaCO_3#
#CaCO_3# =#100# grams per mole
#Ca=1 # x# 40=40#
#C=1 # x# 12=12#
#O=3 # x# 16=48#
#CO_2# =#44# grams per mole
#C=1 # x# 12=12#
#O=2 # x# 16=32# - Find the mass of pure marble;
#mass pure=(actual mass)(purity)#
#mass pure=((10g)(0.50)#
#mass pure=5 g# - Convert mass
#CaCO_3# to mole#CaCO_3#
#5 cancel(g CaCO_3) # x# (1 mol CaCO_3)/(100 cancel(g CaCO_3)#
#0.05 mol CaCO_3# - Find the mol
#CO_2# ; referring to the equation it's observed that both compounds have same number of mole; thus
#CO_2=0.05 mol# - Convert
#250 ml# to Li;#0.25 Li# - Therefore, to find the Molarity(M) use the formula:
#M=(n. mol)/(Li solution)#
#M=(0.05 mol)/(0.25 Li)# #M=0.20 (mol)/(Li)# or#0.20M#
