Question #a32cf

1 Answer
P dilip_k
Mar 11, 2016

See below

Explanation:

#2C_8H_18+25O_2=16CO_2+18H_2O#

you can remember following also
#C_xH_y +(x+y/4)O_2=xCO_2+y/2H_2O#

#=>2C_xH_y +(2x+y/2)O_2=2xCO_2+yH_2O#

Oxidation Number Method
#C_8 H_18+O_2->CO_2+H_2O#
change in oxidation no of C #=>-9/4->+4=25/4unit# oxidation
change in oxidation no of O #=>0->-2=2unit# Reduction
ratio of no of C and O =#2:25/4=8:25#
ratio of no of #C_8H18 # and O# =1:25#
ratio of no of #C_8H18 # and O# =2:50#
ratio of no of #C_8H18 # and# O_2 =2:25#

Related questions
See all questions in Balancing Chemical Equations
Impact of this question
1545 views around the world
You can reuse this answer
Creative Commons License