Question #a1dd4

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Question #a1dd4

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Answer 1 · 2016-05-07T12:35:40

#=2.4mol#

Explanation:

Strength of #NaCl #Solution #=0.8%M=0.8/100(mol)/L#
So the amount of #NaCl#present in 300L of this solution is
#=0.8/100(mol)/cancelLxx300cancelL=2.4mol#

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