Question #8138e

Question

1394 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-28T11:33:02

#a=7" ; "b=1#

Given: #h(x)-> x^2+1" "k(x)-> ax+b#

'~~~~~~~~~~~~~~~~~~~~~~~
Condition 1

#h(0) =k(0) -> (0)^2+1 = a(0)+b#

#=> b=+1#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Condition 2

Now we have: #h(x)-> x^2+1" "k(x)-> ax+1#

#k(2)-> 15=ax+1#

#ax=14#

#a(2)=14#

#a=7#