Question #6965d

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Answer 1 · 2016-02-13T17:27:28

Hydrogen at the cathode.

Oxygen at the anode.

At the -ve cathode water molecules are reduced:

#2H_2O_((l))+2erarrH_(2(g))+2OH_((aq))^-#

#Na^+# ions are also attracted but are not discharged as this requires much more energy in comparison to discharging water.

At the +ve anode #OH^-# ions are attracted and discharged:

#4OH_((aq))^(-)rarrO_(2(g))+2H_2O_((l))+4e#

You will also get water molecules being oxidised:

#2H_2O_((l))rarrO_(2(g))+4H_((aq))^(+)+4e#