In order to make a 1*mol*L^-1 solution of NaNO_2 in water, how many grams of sodium nitrite are necessary?

1 Answer
anor277
Jan 21, 2016

Concentration = ("moles")/("volume of solution"). Here you need a 1 mol*L^-1 solution.

Explanation:

We require, (5*mmol)/(5*mL) = (5xx10^(-3)*mol)/(5xx10^-3*L) = 1 mol L^-1

Note that the m prefix simply means xx10^-3. So mmol*mL^-1 is precisely 1 mol*L^-1.

So to make this volume we simply take a 5 mL volume of 1 mol*L^-1 sodium nitrite.

It would be best to make a stock solution. Accurately weigh 70.00 g of sodium nitrite, and quantitatively transfer this to a 1 L volumetric flask. Fill up to the mark with distilled water, and make sure all the solid is dissolved.

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