What is the general solution of trigonometric equation $sqrt3cotx+1=0$ ?

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Answer 1 · 2016-10-01T07:14:25

General solution of $sqrt3cotx+1=0$ is $x=npi+(2pi)/3$ , where $n$ is an integer.

As $sqrt3cotx+1=0$ , we have

$sqrt3cotx=-1$

or $cotx=-1/sqrt3$

As $cot(pi/3)=1/sqrt3$ and $cot(pi-pi/3)=1/sqrt3$

i.e. $cotx=cot((2pi)/3)$

Now as $cot$ function has a cycle of $pi$ radians or $180^o$ , it repeats after every $pi$ radians or $180^o$ .

General solution of $sqrt3cotx+1=0$ is $x=npi+(2pi)/3$ , where $n$ is an integer.

What is the general solution of trigonometric equation sqrt3cotx+1=0sqrt3cotx+1=0?