Question #8af7e

Question

1702 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-11T15:40:47

#m_(NaCl)=394.2g#

The concentration is related to the mass through the number of mole:

#C_M=n/V#

and the number of mole is related to the mass by:

#n=m/(MM)#

Therefore, we can first calculate the number of mole from the concentration and the volume by:

#n=C_MxxV=4.50(mol)/(cancel(L))xx1.50cancel(L)=6.75mol#

Now from the number of mole we can find the mass by:

#m=nxxMM=6.75cancel(mol)xx58.4 g/(cancel(mol))=394.2g#

Thus we will need to weigh #394.2g# of #NaCl# and add it to #1.50L# of water to prepare #4.50M# solution of sodium chloride.

Here is a video that will show you how to prepare a solution in the lab:
Lab Demonstration | Solution Preparation & Dilution.