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Answer 1 · 2015-11-24T18:21:27

#0.066"mol/l"#

#H_3PO_(4(aq))+3NaOH_((aq))rarrNa_3PO_(4(aq))+3H_2O_((l))#

No. moles #NaOH=cxxv=0.250xx0.0425=0.01#

From the equation we can see that the no. moles of phosphoric acid must be 1/3 of this:

#:.nH_3PO_4=0.01/3=0.0033#

#c=n/v#

So the concentration of the #H_3PO_4# is given by:

#c=0.0033/0.05=0.066"mol/l"#