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Answer 1 · 2016-01-03T18:57:50

The conjugate bases are $F^{-}$ $"F"^-$ and ${ClO}^{-}$ $"ClO"^-$ .

According to the Brønsted-Lowry theory, an acid $HA$ $"HA"$ donates a proton to a base $B$ $"B"$ .

Its conjugate base $A^{-}$ $"A"^-$ is the product remaining after the loss of the proton.

$HF$ $bb"HF"$

The equation for $HF$ $"HF"$ reacting with a base $B$ $"B"$ is

$underbrace("HF")_color(red)("acid") + "B" ⇌ underbrace("F"^-)_color(red)("conjugate base") + "BH"^+$

The conjugate base is $"F"^-$ .

$bb"HClO"$

The equation for $"HClO"$ is

$underbrace("HClO")_color(red)("acid") + "B" ⇌ underbrace("ClO"^-)_color(red)("conjugate base") + "BH"^+$

The conjugate base is $"ClO"^-$ .