# Question #9a2cf

##### 1 Answer

#### Explanation:

As you know, molarity is defined as moles of solute, which in your case is sodium chloride, **liters** of solution.

Now, a *weight by volume* percent concentration is defined as mass of solute *per volume of solution*. In this case, a **for every**

Now, since molarity is determined by **liters** of solution, it's easier to take a

Since you know that **molar mass** to determine how many moles you have

#9.000color(red)(cancel(color(black)("g NaCl"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g NaCl")))) = "0.154 moles NaCl"#

This means that the sample's molarity will be

#c = n/V#

#c = "0.154 moles"/"1.00 L" = color(green)("0.154 M")#

I'll leave the answer rounded to three sig figs, despite the fact that you only have two sig figs for the percent concentration of the solution.

**SIDE NOTE** *The result must be exactly the same regardless of the volume sample you pick for the solution. I recommend using different volume samples to test this out.*