# Question #bfee2

##### 1 Answer

Here's what I got.

#### Explanation:

I'll show you how to solve part **(C)**, and leave the first two to you as practice.

As you know, molarity is defined as *moles of solute* per **liters** of solution. Practically, a solution's molarity tells you how many moles of solute you get in **one liter** of solution.

#color(blue)("molarity" = "moles of solute"/"liters of solution")#

This means that in order to calculate the molarity of a given solution, you need to know two things

how many moles of solute you havewhat the volume of the solution is - expressed inliters

For part **(C)**, your solute will be *glucose*, *molar mass*.

*Molar mass* tells you what the mass of **one mole** of a substance is. Glucose has a molar mass of **one mole** of glucose has a mass of

Now, notice that your mass is given in *milligrams*, *grams* first, then use the molar mass to find the number of moles

#295 color(red)(cancel(color(black)("mg"))) * "1 g"/(1000color(red)(cancel(color(black)("mg")))) = "0.295 g"#

This means that you have

#0.295 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16 color(red)(cancel(color(black)("g")))) = "0.001637 moles C"_6"H"_12"O"_6#

Now focus on finding the volume of the solution *in liters*

#63.2 color(red)(cancel(color(black)("mL"))) * "1 L"/(1000color(red)(cancel(color(black)("mL")))) = "0.06320 L"#

The molarity of the solution will thus be

#c = "0.001637 moles"/"0.06320 L" = color(green)("0.0259 M")#

For parts **(A)** and **(B)**, you don't need to convert anything, since the mass is already given in *grams* and the volume of the solution in *liters*.