Question #33d8c

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Question #33d8c

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Answer 1 · 2015-10-14T13:56:20

The answer is (c) $9$ $9$

Explanation:

Each electron shell corresponds to a different energy level, which is represented by the principal quantum number, $n$ $n$ .

The $M$ $M$ shell designates the third energy level, for which $n = 3$ $n=3$ .

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The relationship between the principal quantum number and the number of orbitals is given by the equation

$no. of orbitals = n^{2}$ $"no. of orbitals" = n^2$

This equation will produce

$n = 1 \Rightarrow no. of orbitals = 1^{2} = 1$ $n = 1 implies "no. of orbitals" = 1^2 = 1$

$n = 2 \Rightarrow no. of orbitals = 2^{2} = 4$ $n = 2 implies "no. of orbitals" = 2^2 = 4$

$n = 3 \Rightarrow no. of orbitals = 3^{2} = 9$ $n=3 implies "no. of orbitals" = 3^2 = 9$

The $M$ $M$ shell will thus contain a total of $9$ $9$ orbitals

one 3s-orbital

three 3p-orbitals

five 3d-orbitals

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Question #33d8c

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