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Answer 1 · 2015-06-18T13:14:32

0.5681 amps

Arunraju-n

We must find out electrical resistance if lamp load and their ratings are given.

current in circuit= current in lamp1 + current in lamp2

#I=I_1+I_2#

#I=220/R_1+220/R_2# [since #I=V/R#]

#I=(220)xxP_1/(V_1^2) +220xxP_2/V_2^2# [since#R=V^2/P#]

where #P_1,V_1&P_2,V_2# are ratings of bulbs respectively.

#I=(220)xx100/220^2+(220)xx25/220^2#

#I=0.4545+0.1136#

#I=0.5681 amps#