Question #b342a

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Question #b342a

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Answer 1 · 2015-06-13T09:26:18

$DeltaE = "+1260. kJ/mol"$

Explanation:

The energy of the $n^(th)$ Bohr orbit for a hydrogen atom, which has $Z=1$ , is given by the equation

$E_n = E_1/n^2$ , where

$E_1$ - the energy of the $1^(st)$ Bohr orbit, equal to $"-1312 kJ/mol"$ ;
$n$ - the energy level;

In your case, the energy of the fifth energy level will be

$E_5 = E_1/5^2 = E_1/25$

$E_5 = ("-1312 kJ/mol")/25 = "-52.48 kJ/mol"$

Therefore, the difference between $E_5$ and $E_1$ will be

$DeltaE = E_5 - E_1$

$DeltaE = -"52.48 kJ/mol" -(-"1312 kJ/mol") = "+1259.5 kJ/mol"$

Rounded to four sig figs, the answer will be

$DeltaE = color(green)("+1260. kJ/mol")$

This tells you that, in order to get 1 mole of electrons from the first energy level to the fifth energy level in a hydrogen atom, you need to provide 1260. kJ.

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Question #b342a

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