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Question #cee00

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il maestro · Stefan V.

Apr 29, 2015

#M_M = 116#

From #PV = nRT#, you get #n= (PV)/(RT)#

#n= (37.6 * 0.45)/(8.314 * 353) = "0.00576 moles"#

Then from #n = "grams"/M_M#, you get

#M_M = "grams"/"n"#

#M_M = "0.668 g"/"0.0576 moles" = "115.97 g/mol"#

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