What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) = 0.08205 atm L / (mol K)?

1 Answer
Stefan V.
Dec 15, 2014

The answer is #5L#.

You can use the ideal gas law, #PV = nRT#, to determine the volume, given the fact that all other variables are known.

First, let's use the equation that has #R = 0.08205 (atm * L)/(mol * K)#. This means that we need to convert the #100.0kPa# pressure to #atm#

#100.0 kPa * (1 atm)/(101.325 kPa) = 0.9869atm#

So, #V = (nRT)/P = (0.2 * 0.08205 * 300)/(0.9869) = 5L# (rounded to 1 sig fig);

As practice and as a way to double-check our result, use the other value of #R# as well; this time, the pressure stays in #kPa# and the volume must come out to be #5L#

#V = (nRT)/P = (0.2 * 8.314 * 300)/(100.0) = 5L#

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