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Answer 1 · 2015-04-22T22:48:50

93.12g

#c=n/v#

Where:

#c# = concentration

#v# =volume

#n# = no. moles

So:

#n=cv#

#n= 0.5xx2.5 = 1.25#

#M_r[KCl]=(39+35.5)=74.5#

So 1 mole weighs 74.5g

So 1.25 mol weighs #1.25xx74.5 = 93.12"g"#

(Approx #A_r# values used)