Question #c44c2

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Answer 1 · 2015-04-05T16:49:41

#w = "-2 kJ"#

Start with the definitions.

#H = U + PV#, so

#ΔH = ΔU + Δ(PV)#

If the pressure is constant,

#ΔH = ΔU + PΔV#

But #w = -PΔV#, so

#ΔH = ΔU – w#

#w = ΔU – ΔH = "-2045 kJ – (-2043 kJ)" = "-2 kJ"#