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Question #9e2ee

1 Answer

Feb 26, 2015

You get:
#y'=1*e^(2x)+x*2e^(2x)=e^(2x)+2xe^(2x)=e^(2x)(2x+1)#
#y''=2e^(2x)(2x+1)+e^(2x)*2=4xe^(2x)+2e^(2x)+2e^(2x)=#
#=4xe^(2x)+4e^(2x)#

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