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Question #0b93d

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Answer 1 · 2015-01-24T08:48:43

The answer is $"260 mL"$ .

Usually, a $"w/v"$ percent concentration is used for saline solutions, which means that a $"0.9%"$ saline solution will have $"9 g"$ of $"NaCl"$ dissolved in enough water to make $"1000 mL"$ of solution.

$"w/v" = ("mass solute")/("volume of solution") * 100$

So, if you need $"9 g"$ to make $"1000 mL"$ of solutions, it's clear that less $"NaCl"$ will produce less $"0.9%"$ solution.

$"0.9" = ("2.3 g NaCl")/("V"_("solution")) * 100 => V_("solution") = ("2.3 g" * "100")/"0.9"$

$V_("solution") = "256 mL"$ , or $"260 mL"$ (rounded to two sig figs).

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