Question #ade66

1 Answer
Stefan V.
Dec 12, 2014

The answer is 2.15g.

A solution's percent concentration by mass is defined as the mass of solute divided by the total mass of the solution and multiplied by 100%.

c= (mass_(solute))/(mass_(solution)) * 100%

Therefore, the mass of solute needed for this solution is

m_(K_2CO_3) = (c * m_(solution))/100 = (5.00% * 43.0)/(100%) = 2.15g

It is important to try and estimate what that mass could be even before calculating it; this could have been done by takin the 1/20th part (the equivalent of 5%) of 43g, which is roughly 2g.

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