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516 mL of a 3.82 M sodium sulfate (#Na_2SO_4#) solution is diluted with 0.875 L of water. What is the new concentration in molarity?

1 Answer

Apr 26, 2016

Approx. #1.4*mol*L^-1#

Explanation:

#"Molarity "= " Moles of solute"/"Volume of solution (L)"#

#=# #(516xx10^-3*cancelLxx3.82*mol*cancel(L^-1))/(0.516*L+0.875*L)#

#=# #(1.97*mol)/(1.391*L)#

#~=# #1.4*mol*L^-1#

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