33.5 mol of $P_4O_10$ contains how many moles of $P$ ?

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Answer 1 · 2016-03-04T23:07:48

33.5 mol of $"P"_4"O"_10$ contain 134 mol of $"P"$ .

$"1 mol P"_4"O"_10$ contains $"4 mol P"$ .

$33.5 color(red)(cancel(color(black)("mol P"_4"O"_10))) × "4 mol P"/(1 color(red)(cancel(color(black)("mol P"_4"O"_10)))) = "134 mol P"$

33.5 mol of P_4O_10P_4O_10 contains how many moles of PP?