20.000 mL aliquots of a phosphoric acid solution with an unknown concentration is titrated with some 0.624 mol/L sodium hydroxide solution.The average volume of the sodium hydroxide added was 24.01 mL. What is the concentration of the phosphoric acid?

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20.000 mL aliquots of a phosphoric acid solution with an unknown concentration is titrated with some 0.624 mol/L sodium hydroxide solution.The average volume of the sodium hydroxide added was 24.01 mL. What is the concentration of the phosphoric acid?

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Answer 1 · 2017-05-31T20:17:57

$[H_{3} P O_{4}] = 0.375 \cdot m o l \cdot L^{- 1}$ $[H_3PO_4]=0.375*mol*L^-1$ .

Explanation:

We assess the reaction............

$H_{3} P O_{4} (a q) + 2 N a O H (a q) \to N a_{2} H P O_{4} (a q) + 2 H_{2} O (l)$ $H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)$

Note that the phosphoric acid is A DIACID not a triacid in aqueous solution, and we use this stoichiometry accordingly.

$Concentration of acid = \frac{0.624 \cdot m o l \cdot L^{- 1} \times 24.01 \times 10^{- 3} \cdot L}{2 \times 20.00 \times 10^{- 3} \cdot L}$ $"Concentration of acid"=(0.624*mol*L^-1xx24.01xx10^-3*L)/(2xx20.00xx10^-3*L)$

$= 0.375 \cdot m o l \cdot L^{- 1}$ $=0.375*mol*L^-1$

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20.000 mL aliquots of a phosphoric acid solution with an unknown concentration is titrated with some 0.624 mol/L sodium hydroxide solution.The average volume of the sodium hydroxide added was 24.01 mL. What is the concentration of the phosphoric acid?

1 Answer

Explanation:

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