117 grams of NaCl are dissolved in water to make 500 mL of solution. Water is then added to this solution to make a total of one liter of solution. The final molarity of the solution will be?

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117 grams of NaCl are dissolved in water to make 500 mL of solution. Water is then added to this solution to make a total of one liter of solution. The final molarity of the solution will be?

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Answer 1 · 2017-08-21T20:38:32

$Option b$ $"Option b"$

Explanation:

$Molarity$ $"Molarity"$ $=$ $=$ $\frac{Moles of solute}{Volume of solution}$ $"Moles of solute"/"Volume of solution"$ , and so we work out the quotient.....

$\frac{\frac{117 \cdot g}{58.44 \cdot g \cdot m o l^{- 1}}}{1 \cdot L} = ? ? ? \cdot m o l \cdot L^{- 1}$ $((117*g)/(58.44*g*mol^-1))/(1*L)=???*mol*L^-1$ .

The initial dilution was there to distract you. We only need the final volume, and the amount of solute dissolved INITIALLY.

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117 grams of NaCl are dissolved in water to make 500 mL of solution. Water is then added to this solution to make a total of one liter of solution. The final molarity of the solution will be?

1 Answer

Explanation:

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