#"1 L"# of #"CO"_2# is passed through red hot coke. The volume becomes #"1.4 L"# at the same temperature and pressure. What is the composition of the products?
1 Answer
Here's what I got.
Explanation:
Start by writing the balanced chemical equation that describes this reaction
#"CO"_ (2(g)) + "C"_ ((s)) -> 2"CO"_ ((g))#
Now, notice that every mole of carbon dioxide that takes part in the reaction produces
This implies that if the sample of carbon dioxide would react completely, you would end up with
In your case, the resulting gaseous mixture has a volume of
If you take
This means that after the reaction is complete, you will be left with
#overbrace((1 - x)color(white)(.)color(red)(cancel(color(black)("L"))))^(color(blue)("volume of unreacted CO"_2)) + overbrace((2x)color(white)(.)color(red)(cancel(color(black)("L"))))^(color(blue)("volume of CO produced")) = 1.4color(red)(cancel(color(black)("L")))#
This will get you
# 1 + x =1.4 implies x= 0.4#
Therefore, you can say that the resulting mixture will contain
#(1 - 0.4)color(white)(.)"L" = "0.6 L " -> " CO"_2#
#(2 * 0.4)color(white)(.)"L" = "0.8 L " -> " CO"#