How do you write #log_2(x)=5# in exponential form?
1 Answer
Aug 12, 2018
Explanation:
#"using the "color(blue)"law of logarithms"#
#•color(white)(x)log_b x=nhArrx=b^n#
#"here "b=2" and "n=5#
#log_2 x=5hArrx=2^5#
