How do you graph #3=rcos(theta-pi/3)#?

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Answer 1 · 2018-08-06T08:58:39

See explanation

#r = p sec (theta - alpha ) rArr p = r cos ( theta - alpha )#

represents the straight line through #N( p, alpha )#, perpendicular

to ON.

Here, N is ( 3, pi/3 ), distant r = 3 from O, in the direction

#theta = alpha = pi/3 = 60^o#.

I think, this is sufficient, for making the graph..

See the graph, with the dot at N..
graph{ (x+y sqrt3 -6)((x-1.5)^2+(y-1.5sqrt3)^2-0.02) = 0[0 10 0 5]}