A 21.5L sample of gas at 107kPa has a temperature of 27.20C. What is the pressure of the gas if it is transferred to a 32.6L container at 44.10C?

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Answer 1 · 2018-08-04T14:44:44

$P_{2} \approx 74.5 kPa$ $P_2 ~~ "74.5 kPa"$

Use

$P V = n R T$ $PV=nRT$

where $n$ $n$ and $R$ $R$ stay constant during the transfer.

$n R = \frac{P V}{T}$ $nR=(PV)/(T)$

so

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $[P_1V_1]/(T_1) = [P_2V_2]/(T_2)$

or

$P_{2} = \frac{P_{1} V_{1} T_{2}}{V_{2} T_{1}}$ $P_2=[P_1V_1T_2]/(V_2T_1)$

Don't forget that

$T = θ+273.15$

So

$P_2 = ("107 kPa" * "21.5 L" * (44.10 + 273.15)\ "K")/("32.6 L" * (27.20 + 273.15) \ "K")$

$P_2 ~~ "74.5 kPa"$