When a supply of hydrogen gas is held in a 4 liter container at 320 K it exerts a pressure of 800 torr. The supply is moved to a 2 liter container, and cooled to 160 K. What is the new pressure of the confined gas?

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When a supply of hydrogen gas is held in a 4 liter container at 320 K it exerts a pressure of 800 torr. The supply is moved to a 2 liter container, and cooled to 160 K. What is the new pressure of the confined gas?

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Answer 1 · 2014-12-19T22:07:48

The answer is $P_{2} = 800$ $P_2 = 800$ $t o r r$ $t o rr$ .

The best way to approach this problem is by using the ideal gas law, $P V = n R T$ $PV = nRT$ . Since the hydrogen is moved from a container to another, we presume that the number of moles remains constant. This will give us 2 equations

$P_{1} V_{1} = n R T_{1}$ $P_1V_1 = nRT_1$ and $P_{2} V_{2} = n R T_{2}$ $P_2V_2 = nRT_2$ . Since $R$ $R$ is a constant as well, we can write

$n R = \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \to$ $nR = (P_1V_1)/T_1 = (P_2V_2)/T_2 ->$ the combined gas law.

Therefore, we have

$P_{2} = \frac{V_{1}}{V_{2}} \cdot \frac{T_{2}}{T_{1}} \cdot P_{1} = \frac{4 L}{2 L} \cdot \frac{160 K}{320 K} \cdot 800 t o r r = 800 t o r r$ $P_2 = V_1/V_2 * T_2/T_1 * P_1 = (4L)/(2L) * (160K)/(320K) * 800t o rr = 800t o rr$ .

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When a supply of hydrogen gas is held in a 4 liter container at 320 K it exerts a pressure of 800 torr. The supply is moved to a 2 liter container, and cooled to 160 K. What is the new pressure of the confined gas?

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