How do you find the slope and intercept of x-y=1?

3 Answers
Jul 28, 2018

See a solution process below.

Explanation:

This equation is in Standard Linear form. The standard form of a linear equation is: color(red)(A)x + color(blue)(B)y = color(green)(C)

Where, if at all possible, color(red)(A), color(blue)(B), and color(green)(C)are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

The slope of an equation in standard form is: m = -color(red)(A)/color(blue)(B)

The y-intercept of an equation in standard form is: color(green)(C)/color(blue)(B)

color(red)(1)x + color(blue)(-1)y = color(green)(1)

Therefore:

  • The slope is: m = (-color(red)(1))/color(blue)(-1) = 1

  • The y-intercept is: color(green)(1)/color(blue)(-1) = -1 or (0, -1)

1, & x-intercept is 1 & y-intercept is -1

Explanation:

Given equation of straight line is

x-y=1

x/1+y/-1=1

The above equation is in standard intercept form of line: x/a+y/b=1 which has

x-intercept: a=1

y-intercept: b=-1

The given equation of line:

x-y=1

y=x-1

The above equation is in standard slope-intercept form: y=mx+c with slope

m=1

Slope: m=1

Jul 30, 2018

Slope: 1, y-intercept -1

Explanation:

Recall slope-intercept form

y=mx+b, with slope m and a y-intercept of b.

We essentially just want a y on the left side. Let's subtract x from both sides to get

-y=-x+1

Next, divide both sides by -1 to get

y=x-1

Now, our equation is in slope-intercept form, with a slope of 1, and a y-intercept of -1.

Hope this helps!