How do you find the amplitude, period, phase shift for $y = sin 2 (x + \frac{3 π}{4})$ $y=sin2(x+(3pi)/4)$ ?

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Answer 1 · 2018-07-28T08:06:35

Please see the explanation below.

Compare this equation to

$y = a sin (ω x + ϕ)$ $y=asin(omegax+phi)$

Here,

$y = sin 2 (x + \frac{3}{4} π) = sin (2 x + \frac{3}{2} π)$ $y=sin2(x+3/4pi)=sin(2x+3/2pi)$

The amplitude is $a = 1$ $a=1$

The period is $T = 2 \frac{π}{2} = π$ $T=2pi/2=pi$

The phase shift is $ϕ = \frac{3}{2} π$ $phi=3/2pi$

graph{sin(2x+3/2pi) [-7.02, 7.024, -3.51, 3.51]}

How do you find the amplitude, period, phase shift for y=sin2(x+(3pi)/4)y=sin2(x+3π4)y=sin2(x+(3pi)/4)?