How do you find the amplitude, period, phase shift for y=sin2(x+(3pi)/4)y=sin2(x+3π4)?

1 Answer
Jul 28, 2018

Please see the explanation below.

Explanation:

Compare this equation to

y=asin(omegax+phi)y=asin(ωx+ϕ)

Here,

y=sin2(x+3/4pi)=sin(2x+3/2pi)y=sin2(x+34π)=sin(2x+32π)

The amplitude is a=1a=1

The period is T=2pi/2=piT=2π2=π

The phase shift is phi=3/2piϕ=32π

graph{sin(2x+3/2pi) [-7.02, 7.024, -3.51, 3.51]}