How do you find the amplitude, period, phase shift for #y=sin2(x+(3pi)/4)#?

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Answer 1 · 2018-07-28T08:06:35

Please see the explanation below.

Compare this equation to

#y=asin(omegax+phi)#

Here,

#y=sin2(x+3/4pi)=sin(2x+3/2pi)#

The amplitude is #a=1#

The period is #T=2pi/2=pi#

The phase shift is #phi=3/2pi#

graph{sin(2x+3/2pi) [-7.02, 7.024, -3.51, 3.51]}