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What is the Cartesian form of #( -3 , (25pi)/12 ) #?

1 Answer

Jul 27, 2018

#(0,-3)#

Explanation:

![ jwilson.coe.uga.edu )

#x=rcostheta = -3cos((25pi)/2)=-3cos(pi/2 + 12pi)#

#=-3cos(pi/2)=0#

#y=rsintheta=-3sin((25pi)/2) = -3sin(pi/2+12pi)#

#=-3sin(pi/2) = -3#

Hence the Cartesian form of #(-3, (25pi)/12)# is #(0,-3)#.

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