How do you solve #5(2x+6)=-4(-5-2x)+3x#?
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#5(2x+6) = -4(-5-2x) + 3x#
Use the distributive property to simplify/expand:
#10x + 30 = 20 + 8x + 3x#
Simplify the right side:
#10x + 30 = 20 + 11x#
Subtract #color(blue)(11x)# from both sides:
#10x + 30 quadcolor(blue)(-quad11x) = 20 + 11x quadcolor(blue)(-quad11x)#
#-x + 30 = 20#
Subtract #color(blue)30# from both sides:
#-x + 30 quadcolor(blue)(-quad30) = 20 quadcolor(blue)(-quad30)#
#-x = -10#
Divide both sides by #color(blue)(-1)#:
#(-x)/color(blue)(-1) = (-10)/color(blue)(-1)#
Therefore,
#x = 10#
Hope this helps!
We can distribute the #5# on the left and the #-4# on the right to get
#10x+30=8x+20+3x#
Next, we can combine the #x# terms on the right to get
#10x+30=11x+20#
To make it easier, I'll switch the sides. I didn't do any math here, I just switched the sides:
#11x+20=10x+30#
We can subtract #10x# from both sides to get
#x+20=30#
Lastly, to completely isolate #x#, let's subtract #20# from both sides to get
#x=10#
Hope this helps!
