Given:
#3x+y=8" "......................Equation(1)#
#2x+5y=5" "...................Equation(2)#
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#color(blue)("This bit is not part of the formal approach.")#
We need one equation with just one unknown.
I am using method by example: known that #color(green)(2=2) color(red)(larr" True"#
Multiply both sides by #color(purple)(3)#
#color(green)(ubrace([2color(purple)(xx3)]) = ubrace([2color(purple)(xx3)])#
#color(green)( color(white)(".d") darr color(white)("dddd.d")darr )#
#color(green)(color(white)("dd") 6color(white)("dd") =color(white)("dd") 6 color(red)(larr" Still true"))#
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#color(blue)("Back to the solution.")#
Multiply both sides of #Eqn(1)# by 5 #color(white)("d") # ( 'to get rid' of the #y#)
#15x+5y=40" "........Equation(1_a)#
#Eqn(1_a) - Eqn(2)#
#15x+5y=40#
#ul(color(white)(1)2x+5y=color(white)(4)5larr" Subtract")#
#13x+0color(white)("d") =35#
Divide both sides by 13
#(13x)/13=35/13#
#x=35/13#
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#color(blue)("Your bit")#
Substitute this into either #Eqn(1) or Eqn(2)# to determine the value of #y#
I will let you do that
