For $f(t)= (t^3-t^2+1,t^2-t)$ what is the distance between $f(2)$ and $f(5)$ ?

Question

1670 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-19T14:37:05

$6 sqrt{265}$

$f(2) = (8 - 4 + 1, 4 - 2) = (5,2)$

$f(5) = (125-25+1,25-5) = (101,20)$

dist = $sqrt{96^2 + 18^2} = sqrt 9540 = sqrt{2 ^ 2 * 3 ^ 2 * 5 * 53 }$

For f(t)= (t^3-t^2+1,t^2-t)f(t)= (t^3-t^2+1,t^2-t) what is the distance between f(2)f(2) and f(5)f(5)?