If the sum of three consecutive multiples of #6# is #72#, what is the biggest of these three multiples?

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Answer 1 · 2018-07-13T18:16:03

#30# is the biggest multiple.

Let the smallest multiple of #6# be #6x#
The next multiple is #6(x+1)#
The biggest multiple is #6(x+2)#

The sum of these multiples is #72#

#6x +6(x+1)+6(x+2) =72#

#6x+6x+6+6x+12 =72#

#18x +18 = 72#

#18x = 72-18 = 54#

#x=3#

The three multiples are #6xx3," "6xx4" " and 6xx5#

# 6xx5 =30# is the biggest

Check:

#18+24+30 = 72#