How do you factor by grouping #7-2x^5-3+2+12#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Dr. K. · Jacobi J. Jul 11, 2018 #2(9-x^5)# Explanation: #7 - 2x^5-3+2+12# =#7-3+2+12 - 2x^5# simplify the numbers = #18- 2x^5# =#(2xx9)-(2xxx^5)# find common factor =#2(9-x^5)# factor out 2 Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 1707 views around the world You can reuse this answer Creative Commons License