How do you differentiate $1/x^-0.4$ ?

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Answer 1 · 2018-07-10T06:14:44

$1/x^-0.4$
$=x^0.4$ [reciprocal]

therefore by power rule
$dy/dx = 0.4x^(0.4-1)$
$dy/dx = 0.4x^-0.6$
which can be rewritten as
$dy/dx=0.4/x^0.6$
or
$dy/dx = 2/(5x^(3/5))$

How do you differentiate 1/x^-0.41/x^-0.4?