How do solve the following linear system?: $3s + 4 = -4t, 7s + 6t + 11 = 0$ ?

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How do solve the following linear system?: $3s + 4 = -4t, 7s + 6t + 11 = 0$ ?

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Answer 1 · 2018-07-05T14:35:49

$s=-2$ and $t=1/2$

Explanation:

From first equation, $s=(-4t-4)/3$ .

After plugging value of $s$ into second one,

$7*(-4t-4)/3+6t+11=0$

$(-28t-28+18t+33)/3=0$

$(5-10t)/3=0$

$5-10t=0$

$10t=5$ , so $t=5/10=1/2$

Thus, $s=((-4)*1/2-4)/3=-2$

Answer 2 · 2018-07-05T14:37:57

Your answer is $-28/10=t$

Explanation:

Here we have two equation
1) $3s + 4 = - 4t$
2) $7s + 6t = 0$

using equation 2 to find value of s

$7s+ 6t = 0$
$7s=-6t$
$s=-(6t)/7$ ....(equation3)

Now put value of s in eq 1

$3((-6t)/7) + 4 =-4t$

$(-18t+28)/7=-4t$

$-18t+28=-28t$

$28= -28t+18t$

$28=-10t$

$-28/10=t$

Now put value of t in equation 3

$s=-(6(-28/10))/7$

$s=6(28/70)$

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How do solve the following linear system?: $3s + 4 = -4t, 7s + 6t + 11 = 0$ ?

2 Answers

Explanation:

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do solve the following linear system?: 3s + 4 = -4t, 7s + 6t + 11 = 0 3s + 4 = -4t, 7s + 6t + 11 = 0 ?

2 Answers

Explanation:

Explanation:

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Impact of this question

How do solve the following linear system?: $3s + 4 = -4t, 7s + 6t + 11 = 0$ ?