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How do you evaluate the integral #intx^10-6x^5+2x^3 dx#?

1 Answer

Jun 28, 2018

#x^11/11-x^6+x^4/2+c#

Explanation:

using the power rule

#intx^ndx=x^(n+1)/(n+1)+c,x!=-1#

#int(x^10-6x^5+2x^3)dx#

#=x^11/11-(6x^6)/6+(2x^4)/4+c#

cancelling down we have

#x^11/11-x^6+x^4/2+c#

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