How do you find two solution to #sin(x) = 1/2#?

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Answer 1 · 2018-06-27T03:06:34

pi/6, and (5pi)/6

#sin x = 1/2#
Trig table and the unit circle give 2 arcs x that have the same sin value (1/2) -->
#x = pi/6#, and #x = pi - pi/6 = (5pi)/6#

Answer 2 · 2018-06-27T10:48:21

Use the symmetry of the graph and your knowledge of some sin values

#sin 30=1/2# [should know this]

The first part of the sin graph is symmetrical about #90^@#

180-30=150

#sin 150=1/2#