How do you simplify and divide #(5xy^2-6y^3+3x^2y^3)/(xy)#?

Question

2080 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-22T16:20:47

#5y-(6x^2)/y+3xy^2#

First, let's simplify by taking out a #y# in the numerator and denominator:

#(cancel(y)(5xy-6y^2+3x^2y^2))/(xcancel(y))#

#(5xy-6y^2+3x^2y^2)/x#

Next, we can divide each term in the numerator by x. Let's separate the megafraction we have into three easier ones:

#(5cancel(x)y)/cancel(x)-(6y^2)/x+(3x^(cancel(2))y^2)/cancel(x)#

#5y-(6x^2)/y+3xy^2#

Hope this helps!!