If I have a triangle where #cos u = -5/7# and #sin u >0#, how do I find the sine, tangent, cotangent, secant, and cosecant of the angle u?

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If I have a triangle where #cos u = -5/7# and #sin u >0#, how do I find the sine, tangent, cotangent, secant, and cosecant of the angle u?

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Answer 1 · 2018-06-22T02:59:07

#cos u = -5/7#
#sin^2 u = 1 - cos^2 u = 1 - 25/49 = 24/49 #
#sin u = (2sqrt6)/7#
#tan u = sin/(cos) = ((2sqrt6)/7)(-7/5) = - (2sqrt6)/5#
#cot u = 1/(tan) = - 5/(2sqrt6) = - (5sqrt6)/12#
#sec u = 1/(cos) = - 7/5#
#csc u = 1/(sin) = 7/(2sqrt6) = (7sqrt6)/12#

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If I have a triangle where #cos u = -5/7# and #sin u >0#, how do I find the sine, tangent, cotangent, secant, and cosecant of the angle u?

1 Answer

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