Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enough of the chlorine gas?
Ca(s) + Cl2(g) → CaCl2(s)
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You will get 46.2 g of calcium chloride.
You know that you will need a balanced chemical equation with masses, moles, and molar masses, etc.
Step 1. Assemble all the information in one place
#M_text(r):color(white)(ml)40.08color(white)(mmmm)110.98#
#color(white)(mmmm)"Ca" + "Cl"_2 → "CaCl"_2#
#m"/g": color(white)(m)16.7#
Step 2. Calculate the moles of #"Ca"#
#"Moles of Ca" = 16.7 color(red)(cancel(color(black)("g Ca"))) × ("1 mol Ca")/(40.08 color(red)(cancel(color(black)("g Ca")))) = "0.4167 mol Ca"#
Step 3 Calculate the moles of #"CaCl"_2#
#"Moles of CaCl"_2 = 0.4167 color(red)(cancel(color(black)("mol Ca")))× ("1 mol CaCl"_2)/(1 color(red)(cancel(color(black)("mol Ca")))) = "0.4167 mol CaCl"_2#
Step 4. Calculate the mass of #"CaCl"_2#
#"Mass of CaCl"_2 = 0.4167 color(red)(cancel(color(black)("mol CaCl"_2))) × "110.98 g CaCl"_2/(1 color(red)(cancel(color(black)("mol CaCl"_2)))) = "46.2 g CaCl"_2#
